SOLUTION: find the angles of a triangle if the second angle is 32 less than three times the first angle and third angle is 28 less than twice the first angle

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Question 586272: find the angles of a triangle if the second angle is 32 less than three times the first angle and third angle is 28 less than twice the first angle
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
find the angles of a triangle if the second angle is 32 less than three times the first angle and third angle is 28 less than twice the first angle
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Let the 1st be "x"
Then the 2nd is "3x-32"
And the 3rd is "2x-28"
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Equation:
x + 3x-32 + 2x-28 = 180
6x - 60 = 180
6x = 240
x = 40 degrees (1st)
3x-32 = 120-32 = 88 degrees (2nd)
2x-28 = 80-28 = 52 degrees (3rd)
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Cheers,
Stan H.