SOLUTION: {x+2y+3z=6, y+2z=0, z=2} solve by substitution

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Question 585932: {x+2y+3z=6, y+2z=0, z=2} solve by substitution
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
x+2y+3z=6
y+2z=0
z=2
solve by substitution
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z is given.
Sub for z in the eqn 2, gives the solution for y.
Sub for y & z in the 1st eqn to find x.