SOLUTION: directions: multiply (y+2x)(x3-2y3+3xy2+x2y) the 3 after x, y, and the 2 after y and 2 after x are exponets.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: directions: multiply (y+2x)(x3-2y3+3xy2+x2y) the 3 after x, y, and the 2 after y and 2 after x are exponets.      Log On


   

Question 58553This question is from textbook algebra1
: directions: multiply
(y+2x)(x3-2y3+3xy2+x2y)
the 3 after x, y, and the 2 after y and 2 after x are exponets. This question is from textbook algebra1

Answer by funmath(2933) About Me  (Show Source):
You can put this solution on YOUR website!
directions: multiply
%28y%2B2x%29%28x%5E3-2y%5E3%2B3xy%5E2%2Bx%5E2y%29
y%28x%5E3-2y%5E3%2B3xy%5E2%2Bx%5E2y%29%2B2x%28x%5E3-2y%5E3%2B3xy%5E2%2Bx%5E2y%29
%28x%5E3y-2y%5E4%2B3xy%5E3%2Bx%5E2y%5E2%29%2B%282x%5E4-4xy%5E3%2B6x%5E2y%5E2%2B2x%5E3y%29 Combine your like terms:
2x%5E4%2Bx%5E3y%2B2x%5E3y%2Bx%5E2y%5E2%2B6x%5E2y%5E2%2B3xy%5E3-4xy%5E3-2y%5E4 I put the equation in decending order by the x terms. It keeps you organized. If I was doing this on paper, I'd do it vertically.
2x%5E4%2B3x%5E3y%2B7x%5E2y%5E2-xy%5E3-2y%5E4
Happy Calculating!!!