Question 585418: Mary is twice as old as John was 3 years ago. In 5 years John will be 1 year older than Mary is now. Find the ages of both people today.
Answer by Schaman_Dempster(26)   (Show Source):
You can put this solution on YOUR website! Let the ages of Mary and John be x and y years respectively today.
3 years ago, age of John was (y-3) years
Since Mary is twice as old as john was 3 years ago.
So, x = 2(y-3)
or x = 2y - 6 -------- (1)
In 5 years, age of John will be = (y + 5) years
"John will be 1 year older than Mary is now"
So, (y+5) = x + 1
or x = y + 5 -1
or x = y + 4 --------(2)
Using equation (1) and (2), we get:
2y - 6 = y + 4
2y = y + 4 + 6
2y = y + 10
y = 10
Plugging back the value of y in equation (2)
x = 10 + 4
x = 14
Hence, Age of Mary today is x= 14 years and age of John today is y=10 years.
Hope this helps~!
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