SOLUTION: find the terms a2 a3 a4 and a5 of a geometric sequence if a1=10 and the common ratio r=-1

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Question 585320: find the terms a2 a3 a4 and a5 of a geometric sequence if a1=10 and the common ratio r=-1
Answer by Schaman_Dempster(26) About Me  (Show Source):
You can put this solution on YOUR website!
a1 = 10, r =-1
nth term of a geometric sequence is given by: +xn+=+a1%2Ar%5E%28n-1%29+
So, a2 = a1*r^(2-1) = a1*r = 10*(-1) = -10
a3 = a1*r^(3-1) = a1*r^2 = 10*(-1)^2 = 10*1 = 10
a4 = a1*r^(4-1) = a1*r^3 = 10*(-1)^3 = 10*(-1) = -10
a5 = a1*r^(5-1) = a1*r^4 = 10*(-1)^4 = 10*1 = 10
Hope this helps~!