SOLUTION: 6([n]-3)-4[n]+5=11 How do I solve this? Please I can't get it.

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Question 585196: 6([n]-3)-4[n]+5=11 How do I solve this? Please I can't get it.
Found 2 solutions by ankor@dixie-net.com, Alan3354:
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
6([n]-3)-4[n]+5=11
we can write it:
6(n-3) - 4n + 5 = 11
multiply what's inside the brackets
6n - 18 - 4n + 5 = 11
combine like terms
6n - 4n - 18 + 5 = 11
2n - 13 = 11
add 13 to both sides
2n = 11 + 13
2n = 24
divide both sides by 2
n = 24/2
n = 12
;
:
Check this for yourself
6([n]-3)-4[n]+5=11
replace n with 12
6(12-3)-4[12]+5=11
6(9) - 48 + 5 = 11
54 - 48 + 5 = 11
6 + 5 = 11
:
Do you "get it" now? Any questions? C

Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
6([n]-3)-4[n]+5=11
6(n-3)-4n+5=11 The brackets did nothing
6n-18 - 4n+5 = 11
2n - 13 = 11
2n = 24
n = 12