Question 585077: lnx-3ln3=3
ln3x=6
lne^2/2
ln(2x-1)=0
I just don't understand how to work these out. I'd appreciate you help.
Answer by Alan3354(69443)   (Show Source):
You can put this solution on YOUR website! lnx-3ln3=3
ln(x) - 3ln(3) = 3
ln(x) - ln(27) = 3 3^3 = 27
ln(x/27) = 3 Subtracting exponents --> division (logs are exponents)
ln(x/27) = ln(e^3) True of any number
x/27 = e^3
x = 27e^3
x =~ 542.31
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ln3x=6
ln(3x) = 6
Similar to the one above
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lne^2/2
= ln(e^2) - ln(2)
= 2 - ln(2)
=~ 1.30685
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ln(2x-1)=0
If the log = 0, the argument is 1, for any base
2x-1 = 1
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Or,
2x-1 = e^0
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