SOLUTION: if the difference of an integer squared and twice the integer is 63, find the integer I set it up as x^2 -2x = 63 and then factored bu I don't think it is right

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Question 584897: if the difference of an integer squared and twice the integer is 63, find the integer

I set it up as x^2 -2x = 63
and then factored bu I don't think it is right
Found 2 solutions by richwmiller, JBarnum:
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!

x^2 -2x = 63
x^2 -2x - 63=0
(x+7)*(x-9)=0
x=9 and x=-7

Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
right setup
you just didnt use the quadratic formula?
x%5E2+-2x+=+63
x%5E2-2x-63=0
-9 and 7
-9 times 7 = -36
-9 plus 7 = -2
so:
%28x-9%29%28x%2B7%29=0
x=9,-7
two possible answers