SOLUTION: Find the mean, variance,and binomial distribution with the given values of n and p. n=122,p=0.24 The mean is: _____ (round to the nearest tenth as needed) The variance is:

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Question 584876: Find the mean, variance,and binomial distribution with the given values of n and p.
n=122,p=0.24
The mean is: _____ (round to the nearest tenth as needed)
The variance is:_____(round to the nearest tenth as needed)
The standard divination is: _____(round to the nearest tenth as needed)
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
Mean:
mu = np = 122*0.24 = 29.28

So the mean is 29.3 (rounded to the nearest tenth)

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Variance:
sigma^2 = np(1-p) = 122*0.24(1-0.24) = 22.2528

So the variance is 22.3 (rounded to the nearest tenth)
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Standard Deviation:

sigma = sqrt(np(1-p)) = sqrt(122*0.24(1-0.24)) = 4.717287

So the standard deviation is 4.7 (rounded to the nearest tenth)

SOLUTION: Find the mean, variance,and binomial distribution with the given values of n and p. n=122,p=0.24 The mean is: _____ (round to the nearest tenth as needed) The variance is:_