SOLUTION: My grade in a certain math class is determined by three tests. My highest test score will count for 50%
of my grade and my lowest for 20%; the "middle" test score will count for 3
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of my grade and my lowest for 20%; the "middle" test score will count for 3
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Question 584818: My grade in a certain math class is determined by three tests. My highest test score will count for 50%
of my grade and my lowest for 20%; the "middle" test score will count for 30%. I must have a weighted
average of 60 in order to pass the class. If I have already earned scores of 70 on my first two tests,
what is the lowest score I can earn on the third test for which I will still pass the class? Found 2 solutions by richwmiller, solver91311:Answer by richwmiller(17219) (Show Source):
You can put this solution on YOUR website! .5x+.3y+.2z=60
x>y>z
if x=100 then .5*100+.3*70+.2*70=85
if z=20 then .5*70+.3*70+.2*20=60
If you get a 20 on the third test, your average will be 60
If you score greater than 70 on the third test, then obviously the weighted average will be greater than 70, hence the minimum score on the third test in order to reach a weighted average of 60 must be a score less than 70. That means that the top and middle scores will, in fact, be 70.
So, your weighted average will be:
Where is the score on the third test.
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Super Double Plus Extra Credit: True or False: If the scores on the first two tests had been 75, you could sleep in the day of the test.
John
My calculator said it, I believe it, that settles it
