Question 584716: i have a right angled triangle, a=y b=4y and c=20.6 i need to find y, i keep coming up with the wrong answer, i start with sqrt4*y^2+y^2=20.6 i keep comming up with y =9.21 but that doesent work for 4y? any help is appreciated
Answer by Schaman_Dempster(26)   (Show Source):
You can put this solution on YOUR website!
Hello there, I see what you have been missing. I will provide the step by step solution below:
sqrt(a^2 + b^2) = c
sqrt( (4y)^2 + y^2 ) = 20.6
sqrt( 16y^2 + y^2) = 20.6
sqrt(17 y^2 ) = 20.6
Squaring on both the sides, we get:
17 y^2 = 424.36
Dividing both the sides by 17, we get:
y^2 = 424.36/17
y^2 = 24.96235294117647
y = 4.996233875748459 , y = - 4.996233875748459
Since y is the length of one of the sides, it can not hold a negative value.
Thus, y = 4.996233875748459
One can round off the answer to 3 decimal places as: y = 4.996
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