an airplane over the pacific sights an atoll at a 5ー
angle of depression. If the plane is 450 meters above
water, how many kilometers is it from a point 450
meters above the atoll.
x
P覧覧覧覧覧覧覧覧覧覧覧覧覧覧覧猷
. 5ー |
. |450 m
. |
.
A
Let the plane be at point P, the atoll at point A,
and let Q be the point 450 m above the atoll at A.
We want to find the distance PQ, which we will call x.
QA = 450, and it is the side opposite the 5ー angle in
right triangle PQA.
PO = x = the side adjacent the 5ー angle in right
triangle PQA.
So since we are given the opposite side, and we want
to find the adjacent side, we use the only one of the
basic three trigonometric functions that involves the
opposite and the adjacent, which is the tangent. So
opp
tan 5ー = -----
adj
450
tan 5ー = -----
x
Multiply both sides by x:
x tan 5ー = 450
Divide both sides by tan 5ー:
450
x = --------
tan 5ー
Use a calculator
450
x = --------------
.0874886635
x = 5142.523535
Since 450 is rounded probably to the
nearest 10 feet, we probably should round
the final answer likewise, to 5140 feet.
Edwin