SOLUTION: (x-3)^2+(y+1)^2=4 so where is the circle supposed to be on a graph?

Algebra ->  Quadratic-relations-and-conic-sections -> SOLUTION: (x-3)^2+(y+1)^2=4 so where is the circle supposed to be on a graph?      Log On


   

Question 584622: (x-3)^2+(y+1)^2=4 so where is the circle supposed to be on a graph?
Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
(x-3)^2+(y+1)^2=4 so where is the circle supposed to be on a graph?
This is an equation of a circle with center at (3,-1) and radius=2
So, with a compass set 2 units apart, place the pointer on point (3,-1) and draw a circle with a radius=2.