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| Question 584510:  Please help me find the vertice and foci for this ellipse:
   Answer by lwsshak3(11628)
      (Show Source): 
You can put this solution on YOUR website! find the vertices and foci for this ellipse: x^2+9y^2=18
 divide by 18
 x^2/18+y^2/2=1
 This is an equation of an ellipse with horizontal major axis of the standard form:
 (x-h)^2/a^2+(y-k)^2/b^2=1, a>b, (h,k) being the (x,y) coordinates of the center.
 For given equation:
 center(0,0)
 a^2=18
 a=√18≈4.24
 vertices=(0±a,0)=(0±√18,0)=(0±4.24,0)=(-4.24,0) and (4.24,0)
 ..
 b^2=2
 b=√2≈1.41
 ..
 Foci:
 c^2=a^2-b^2=18-2=16
 c=√16=4
 Foci=(0±c,0)=(0±4,0)=(-4,0) and (4,0)
 
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