Question 58438: Graph y=(x-5)(2x+7)(3-x)^2(x-7)(x+2)^2, and label all intercepts
ty
Answer by Nate(3500)   (Show Source):
You can put this solution on YOUR website! y-intercept
y = (x - 5)(2x + 7)(3 - x)^2(x - 7)(x + 2)^2
y = (0 - 5)(2*0 + 7)(3 - 0)^2(0 - 7)(0 + 2)^2
y = (5)(7)(3)^2(7)(2)^2 = 35*9*7*4 = 8820
(0,8820)
x-intercepts
y = (x - 5)(2x + 7)(3 - x)^2(x - 7)(x + 2)^2
0 = (x - 5)(2x + 7)(3 - x)^2(x - 7)(x + 2)^2
x - 5 = 0
2x + 7 = 0
3 - x = 0
x - 7 = 0
x + 2 = 0
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
x = 5
x = -7/2
x = 3
x = 7
x = -2
(5,0), (-7/2,0), (3,0), (7,0), (-2,0)
|
|
|
