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Question 584017: how can you find the focus of this equation y plus 1 over 1 = ( x - 3 over 2 ) squared
Answer by lwsshak3(11628)   (Show Source):
You can put this solution on YOUR website! how can you find the focus of this equation y plus 1 over 1 = ( x - 3 over 2 ) squared
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(y+1)/1=((x-3)/2)^2
(y+1)=((x-3)^2/4
4(y+1)=(x-3)^2
(x-3)^2=4(y+1)
Standard form of equation for a parabola that opens upwards:
(x-h)^2=4p(y-k), (h,k) being the (x,y) coordinates of the vertex
For given equation of parabola: (x-3)^2=4(y+1)
vertex: (3,-1)
axis of symmetry: x=-3
4p=4
p=1
focus: (3,-1+p)=(3,-1+1)=(3,0) (p-unit above the vertex on the axis of symmetry)
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