SOLUTION: How many liters of a 10% alcohol solution must be mixed with 80 liters of a 80% solution to get a 50% solution?

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Question 583711: How many liters of a 10% alcohol solution must be mixed with 80 liters of a 80% solution to get a 50% solution?
Answer by richwmiller(17219) About Me  (Show Source):
You can put this solution on YOUR website!
.1*x+80*.8=(x+80)*.5
x=60 liters of 10% solution