SOLUTION: a cyclist rode the first 36-mile portion of his workout at a constant speed.for the 30-mile cooldown portion of his workout, he reduced his speed by 2 miles per hour. Each portion

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Question 583603: a cyclist rode the first 36-mile portion of his workout at a constant speed.for the 30-mile cooldown portion of his workout, he reduced his speed by 2 miles per hour. Each portion of the workout took the same time. Find the cyclist's speed during the first portion and find his speed during the cooldown portion.
Answer by ankor@dixie-net.com(22740) (Show Source):
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a cyclist rode the first 36-mile portion of his workout at a constant speed.
For the 30-mile cooldown portion of his workout, he reduced his speed by 2 miles per hour.
Each portion of the workout took the same time.
Find the cyclist's speed during the first portion and find his speed during the cooldown portion.
:
let s = his speed on the 1st 36 mi
then
(s-2) = his speed on the last 30 mi
:
Write time equation, time = dist/speed
:
workout time = cooldown time
=
Cross multiply
36(s-2) = 30s
36s - 72 = 30s
36s - 30s = 72
6s = 72
s = 12 mph his workout speed
then
10 mph his cooldown speed
:
:
Check this by finding the actual times, they should be equal
36/12 = 3 hrs
30/10 = 3 hrs