SOLUTION: 10 years ago a father was 6 times as old as his daughter. 10 years later he is twice as old as his daughter.what would be their present age.

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Question 583574: 10 years ago a father was 6 times as old as his daughter. 10 years later he is twice as old as his daughter.what would be their present age.
Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
f=father d=daughter
f-10=6%28d-10%29 (10 years ago a father was 6 times as old as his daughter)
f%2B10=2%28d%2B10%29 (10 years later he is twice as old as his daughter)
.
f-10=6d-60
f=6d-50
.
f%2B10=2d%2B20
f=2d%2B10
.
2d%2B10=6d-50
2d%2B60=6d
60=4d
15=d
.
f=2%2815%29%2B10
f=30%2B10
f=40