SOLUTION: I am having trouble finding the midpoint of the square roots. I got one of the problems right, but now I can't seem to get this one right. Please help! (2 square root of 5, 3 sq

Algebra ->  Square-cubic-other-roots -> SOLUTION: I am having trouble finding the midpoint of the square roots. I got one of the problems right, but now I can't seem to get this one right. Please help! (2 square root of 5, 3 sq      Log On


   

Question 583561: I am having trouble finding the midpoint of the square roots. I got one of the problems right, but now I can't seem to get this one right. Please help!
(2 square root of 5, 3 square root of 3) (3 square root of 5, negative square root of 3)
Answer by Alan3354(69443) About Me  (Show Source):
You can put this solution on YOUR website!
I am having trouble finding the midpoint of the square roots. I got one of the problems right, but now I can't seem to get this one right. Please help!
(2 square root of 5, 3 square root of 3) (3 square root of 5, negative square root of 3)
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If those are 2 points and you want the mid-point:
Find the average of x & y separately.
For x: %282sqrt%285%29+%2B+3sqrt%285%29%29%2F2+=+2.5sqrt%285%29
For y: %283sqrt%283%29+-+sqrt%285%29%29%2F2+=+sqrt%283%29
--> (5sqrt(5)/2,sqrt(3))