Question 58317: Prove that the diagonals of a parallelogram bisect each other.
Answer by Nate(3500)   (Show Source):
You can put this solution on YOUR website! Just graph a square on a cartesian coordinate plain.
P(1,1), N(-1,1), S(-1,-1), and M(1,-1)
The points that make the diagonals: (-1,1) and (1,-1) <~> (1,1) and (-1,-1)
Slope of (-1,1) and (1,-1)
m = (-1 - 1)/(1 + 1) = -2/2 = -1
Slope of (1,1) and (-1,-1)
m = (1 + 1)/(1 + 1) = 2/2 = 1
The slope of one is the inverse of it's negative counterpart. The lines are perpendicular. Now, you may have to put that in a proof; I do not if your school wants you to do so.
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