SOLUTION: 1. Lisa has $1.75. She has twice as many nickels than dimes. How many of each. 2. Bob has $2.75. He has nickels, dimes, and quarters. How many of each does he have.

Algebra ->  Customizable Word Problem Solvers  -> Coins -> SOLUTION: 1. Lisa has $1.75. She has twice as many nickels than dimes. How many of each. 2. Bob has $2.75. He has nickels, dimes, and quarters. How many of each does he have.      Log On

Ad: Over 600 Algebra Word Problems at edhelper.com


   



Question 583103: 1. Lisa has $1.75. She has twice as many nickels than dimes. How many of each.
2. Bob has $2.75. He has nickels, dimes, and quarters. How many of each does he have.

Found 2 solutions by solver91311, JBarnum:
Answer by solver91311(24713) About Me  (Show Source):
You can put this solution on YOUR website!


1. This problem has no solution. In order to have $1.75 consisting of only dimes and nickels, you have to have an odd number of nickels. But no matter how many dimes you have, twice as many is an even number. You cannot simultaneously have an odd number of nickels and an even number of nickels.

John

My calculator said it, I believe it, that settles it
The Out Campaign: Scarlet Letter of Atheism


Answer by JBarnum(2146) About Me  (Show Source):
You can put this solution on YOUR website!
2 is unknow i can list several possible answers
3q 10d 20n
2q 20d 5n
8q 7d 1n
.... soo many possibilities
1 looks solvable
n=2d
if d=9 n=18 and thats $1.80...hmmm
1.75=.1d+.05(2d)
1.75=.2d
8.75=d
well this means this is a bogus question as u cant have 3/4 of a dime
both questions are a fail and waste of time