SOLUTION: Write the expression as a sum and/or difference of logarithms. Express powers as factors. I'm lost in this problem, can anyone help? ln [ ( x - 4 )^2 / x^2 - 1 ]^2/3 x>4

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Write the expression as a sum and/or difference of logarithms. Express powers as factors. I'm lost in this problem, can anyone help? ln [ ( x - 4 )^2 / x^2 - 1 ]^2/3 x>4      Log On


   



Question 582865: Write the expression as a sum and/or difference of logarithms. Express powers as factors. I'm lost in this problem, can anyone help?
ln [ ( x - 4 )^2 / x^2 - 1 ]^2/3 x>4

Answer by lwsshak3(11628) About Me  (Show Source):
You can put this solution on YOUR website!
Write the expression as a sum and/or difference of logarithms. Express powers as factors. I'm lost in this problem, can anyone help?
ln [ ( x - 4 )^2 / x^2 - 1 ]^2/3 x>4
ln [ ( x - 4 )^2 / x^2 - 1 ]^2/3
(2/3)ln [ ( x - 4 )^2 / x^2 - 1 ]
(2/3) [ln ( x - 4 )^2-ln (x^2 - 1) ]
(2/3) [2ln ( x - 4 )-ln (x^2 - 1) ]