Question 58285This question is from textbook Beginning Algebra
: Can someone help me work out this problem?
I need to solve the following problem and show the equation used for the solution:
Jill has $3.50 in nickels and dimes. If she has 50 coins, how many of each type of coin does she have?
Thanks,
Ashley
This question is from textbook Beginning Algebra
Answer by rcmcc(152)   (Show Source):
You can put this solution on YOUR website! Hello Ashley,
we can solve this question by setting up a set of linear equations.
let the nickels be x and dimes be y
since we have 50 coins both x+y=50
because their face value is .05 and .1 and they add up to 3.50 we can state .05x+.1y=3.50
now we can solve
x+y=50
.05x+.1y=3.50
isolate y in the bottom equation
.05x+.1y=3.50
subtract .05x
.1Y=3.5-.05x
divide by .1
y=35-.5X
now you can substitute in the equation for y in the first equation.
x+(35-.5x)=50
you can simplify the equation
.5x+35=50
subtract 35 from each side
.5X=15
now divide by .5
x=30
there are 30 nickels, since you have 50 coins, you have 20 dimes as well.
we can check this answer
30(.05)+20(.10)=
$1.5+2.0=$3.50
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