SOLUTION: How do you solve ,the square root of 10 subtracted from (x) is equal to one minus the square root of x.

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Question 582720: How do you solve ,the square root of 10 subtracted from (x) is equal to one minus the square root of x.
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+x+-+sqrt%2810%29+=+1+-+sqrt%28x%29+
Add +sqrt%28x%29+ to both sides
Add +sqrt%2810%29+ to both sides
+x+%2B+sqrt%28x%29+=+sqrt%2810%29+%2B+1+
------------------------
Let +x+=+z%5E2+
+z%5E2+%2B+z+=+sqrt%2810%29+%2B+1+
Complete the square
+z%5E2+%2B+z+%2B+%281%2F2%29%5E2+=+sqrt%2810%29+%2B+1+%2B+%281%2F2%29%5E2+
+z%5E2+%2B+z+%2B+1%2F4+=+sqrt%2810%29+%2B+1+%2B+1%2F4+
+%28+z+%2B+1%2F2%29%5E2+=+sqrt%2810%29+%2B+5%2F4+
Take the square root of both sides
+z+%2B+1%2F2+=+sqrt%28+sqrt%2810%29+%2B+5%2F4+%29+
+sqrt%28x%29+%2B+1%2F2+=+sqrt%28+sqrt%2810%29+%2B+5%2F4+%29+
+sqrt%28x%29++=+sqrt%28+sqrt%2810%29+%2B+5%2F4++%29+-+1%2F2+
Square both sides
+x+=+sqrt%2810%29+%2B+5%2F4+-+sqrt%28+sqrt%2810%29+%2B+5%2F4%29+%2B+1%2F4+
+x+=+sqrt%2810%29++-++sqrt%28+sqrt%2810%29+%2B+5%2F4%29+%2B+3%2F2+
This looks pretty strange. You might want
a 2nd opinion