SOLUTION: A biologist finds that 22% of fruit flies have short wings and 37% have eye defects. Assuming these two events are independent, what is the probability that a randomly selected fr

Algebra ->  Probability-and-statistics -> SOLUTION: A biologist finds that 22% of fruit flies have short wings and 37% have eye defects. Assuming these two events are independent, what is the probability that a randomly selected fr      Log On


   



Question 582698: A biologist finds that 22% of fruit flies have short wings and 37% have eye defects. Assuming these two events are independent, what is the probability that a randomly selected fruit fly has neither short wings nor eye defects?
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
A biologist finds that 22% of fruit flies have short wings and 37% have eye defects. Assuming these two events are independent, what is the probability that a randomly selected fruit fly has neither short wings nor eye defects?
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P(not short wings AND not eye defects) = P(not sw)*P(not ed)
= 0.78*0.63
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= 0.4914
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Cheers,
Stan H.