SOLUTION: Find the equation for the circle with the center (5,-3) and passing through (-1,-4) Thank you very much!

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Question 582551: Find the equation for the circle with the center (5,-3) and passing through (-1,-4)
Thank you very much!
Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!
%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2 Start with the general equation of a circle.


%28x-5%29%5E2%2B%28y--3%29%5E2=r%5E2 Plug in h=5 and k=-3 (since the center is the point (h,k) ).


%28-1-5%29%5E2%2B%28-4--3%29%5E2=r%5E2 Plug in x=-1 and y=-4 (this is the point that lies on the circle, which is in the form (x,y) ).


%28-6%29%5E2%2B%28-1%29%5E2=r%5E2 Combine like terms.


36%2B1=r%5E2 Square each term.


37=r%5E2 Add.


So because h=5, k=-3, and r%5E2=37, this means that the equation of the circle with center (5,-3) that goes through the point (-1,-4) is %28x-5%29%5E2%2B%28y%2B3%29%5E2=37.