Question 5824: find the equation of the line parallel to the graph of 4x+2y=8 and containing (-1,5)
This was an example in my book, and they said to solve it, but they dont show how, so i'm just wondering, how would i go about solving this. I tried solving this and got y=2x+7 , but i'm not so sure that this is right. Help!
Answer by longjonsilver(2297)   (Show Source):
You can put this solution on YOUR website! first get this into the y=mx+c form, so that we then can know some things about the line...
4x+2y=8 --> subtract 4x from both sides
2y = -4x + 8 --> divide both sides by 2
y = -2x + 4
this is now in the y=mx+c form...where m=-2. This is the gradient.
Any line parallel to this one will have the same gradient, so our new streaight line will be y = -2x+c. What is the value of c?. Well to find that from this equation we need to know x and y...which we do. The question gave us (-1, 5). So,
5 = -2(-1) + c
5 = 2 + c
3 = c
--> equation of line is therefore y = -2x+3
jon.
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