SOLUTION: Please help me solve this equation:
Equation of line passing through (-7,-9) and perpendicular to 8x-9y+2=0
What I've tried: y=-8/9x+2/9 PL: y=9/8x+b EQUALS -9=9/8(-7)+b ???
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-> SOLUTION: Please help me solve this equation:
Equation of line passing through (-7,-9) and perpendicular to 8x-9y+2=0
What I've tried: y=-8/9x+2/9 PL: y=9/8x+b EQUALS -9=9/8(-7)+b ???
H
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Question 582392: Please help me solve this equation:
Equation of line passing through (-7,-9) and perpendicular to 8x-9y+2=0
What I've tried: y=-8/9x+2/9 PL: y=9/8x+b EQUALS -9=9/8(-7)+b ???
Help please. Found 2 solutions by josmiceli, KMST:Answer by josmiceli(19441) (Show Source):
You can put this solution on YOUR website! In general, if the line is ,
then the line perpendicular to it has a slope
given:
Any line perpendicular to this one has slope
------------------
given that the line passes through (-7,-9 )
Now use the point-slope formula:
Multiply both sides by
Here's a plot of the 2 lines:
You can put this solution on YOUR website! --> --> or
The slope of the given line is .
A perpendicular line will have a slope of
Setting up an equation such as and solving for b would work. --> --> --> -->
Otherwise, the point slope form of the equation is --> --> --> --> --> -->