SOLUTION: A motorcycle breaks down and the rider must walk the rest of the way to work. The motorcycle was being driven at 45mph, and the rider walks at a speed of 6mph. The distance from ho

Algebra ->  Percentage-and-ratio-word-problems -> SOLUTION: A motorcycle breaks down and the rider must walk the rest of the way to work. The motorcycle was being driven at 45mph, and the rider walks at a speed of 6mph. The distance from ho      Log On


   

Question 582334: A motorcycle breaks down and the rider must walk the rest of the way to work. The motorcycle was being driven at 45mph, and the rider walks at a speed of 6mph. The distance from home to work is 25miles, and the time for the trip was 2hr. How far did the motorcyle go before it broke down?
Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
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A motorcycle breaks down and the rider must walk the rest of the way to work.
The motorcycle was being driven at 45mph, and the rider walks at a speed of 6mph.
The distance from home to work is 25miles, and the time for the trip was 2hr.
How far did the motorcycle go before it broke down?
:
Let m = distance rode on the motorcycle
then
(25-m) = distance he walked
:
Write a time equation: time = dist/speed
:
ride time + walk time = 2 hrs
m%2F45 + %28%2825-m%29%29%2F6 = 2
multiply by LCM of the denominators, 90 will do it, results:
2m + 15(25-m) = 90(2)
:
2m + 375 - 15m = 180
2m - 15 m = 180 - 375
-13m = -195
13m = 195
m = 195/13
m = 15 mi on the motorcycle
:
:
Check this by finding the actual times
15/45 = .33
10/6 = 1.67
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tot time: 2 hrs