SOLUTION: The perimeter of a rectangle is 50 meters. The width of the rectangle is 5 meters less than the length. Determine the equation that would solve for the length and width of the rect
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Question 582092: The perimeter of a rectangle is 50 meters. The width of the rectangle is 5 meters less than the length. Determine the equation that would solve for the length and width of the rectangle Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website! The perimeter of a rectangle is 50 meters. The width of the rectangle is 5 meters less than the length. Determine the equation that would solve for the length and width of the rectangle
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Let length be "x".
The width is "x-5"
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Perimeter = 2(length + width)
50 = 2(x + (x-5))
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Cheers,
Stan H.
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