SOLUTION: Please help me solve the following,I am stumped. One canned juice drink is 25% orange juice, another is 10% orange juice. How many liters of each should be mixed together in order
Algebra ->
Customizable Word Problem Solvers
-> Mixtures
-> SOLUTION: Please help me solve the following,I am stumped. One canned juice drink is 25% orange juice, another is 10% orange juice. How many liters of each should be mixed together in order
Log On
Question 582000: Please help me solve the following,I am stumped. One canned juice drink is 25% orange juice, another is 10% orange juice. How many liters of each should be mixed together in order to get 15 liters that is 14% orange juice?
Thank you for your help Answer by ankor@dixie-net.com(22740) (Show Source):
You can put this solution on YOUR website! One canned juice drink is 25% orange juice, another is 10% orange juice.
How many liters of each should be mixed together in order to get 15 liters that is 14% orange juice?
:
Two equations:
:
Total amt of juice
a + b = 15
b = (15-a); use this form for substitution
:
Percent juice amt
.25a + .10b = .14(15)
replace b with (15-a)
.25a + .10(15-a) = 2.1
.25a + 1.5 - .10a = 2.1
.25a - .10a = 2.1 - 1.5
.15a = .6
a = .6/.15
a = 4 liter so 25% juice
:
you can find b, the amt of 10% juice
