SOLUTION: The equation used to predict the total body weight (in pounds) of a female athelit from a certian high school is y (greater than symbol over the y) =neg 115+3.04x(one below x) +1.2

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Question 581980: The equation used to predict the total body weight (in pounds) of a female athelit from a certian high school is y (greater than symbol over the y) =neg 115+3.04x(one below x) +1.26x (2 below x) where x(one below x) is the females athelites height (in inches) and x( two below the x) is the female athelites percent body fat. Use the motiple regression equation to predict the total body weight for the female athlete who is 68 inches talland has 23% body fat.
The predicted total body weight for the female athlete who is 68 inches talland has 23% body fat is _____ pounds. (Round to the nearest tenth as needed)

Found 2 solutions by jim_thompson5910, stanbon:
Answer by jim_thompson5910(35256) (Show Source):
You can put this solution on YOUR website!
$\huge \hat{y} = -115+3.04x_{1} +1.26x_{2}$

$\huge \hat{y} = -115+3.04(68) +1.26(23)$

$\huge \hat{y} = -115+206.72 +28.98$

$\huge \hat{y} = 120.7$

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Answer:

The predicted total body weight for the female athlete who is 68 inches talland has 23% body fat is _120.7_ pounds.

Answer by stanbon(75887) (Show Source):
You can put this solution on YOUR website!
The equation used to predict the total body weight (in pounds) of a female athelit from a certian high school is y (greater than symbol over the y) =neg 115+3.04x(one below x) +1.26x (2 below x) where x(one below x) is the females athelites height (in inches) and x( two below the x) is the female athelites percent body fat.
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Use the motiple regression equation to predict the total body weight for the female athlete who is 68 inches talland has 23% body fat.
The predicted total body weight for the female athlete who is 68 inches talland has 23% body fat is _____ pounds. (Round to the nearest tenth as needed)
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y = -115+3.04x1 +1.26x2 where x1 is the female athlete's height (in inches) and x3 is the female athlete's percent body fat.
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y = -115 + 3.04*68 + 1.26*23
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y = 120.7
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Cheers,
Stan H.