You can put this solution on YOUR website! log2(x - 2) + log2(x + 1) = log2 10
log2(x - 2)(x + 1) = log2 10
(x - 2)(x + 1) = 10
x^2+x-2x-2 = 10
x^2-x-2 = 10
x^2-x-12 = 0
(x-4)(x+3) = 0
x = {-3, 4}
The -3 is an "extraneous" solution so we throw it out leaving:
x = 4