SOLUTION: "x" pounds of candy valued at $3.50 per pound is mixed with "y" pounds of candy valued at $4.30 per pound to produce 10 pounds of a mixture selling for $4 per pound. Find "x" and "

Algebra ->  Coordinate Systems and Linear Equations  -> Linear Equations and Systems Word Problems -> SOLUTION: "x" pounds of candy valued at $3.50 per pound is mixed with "y" pounds of candy valued at $4.30 per pound to produce 10 pounds of a mixture selling for $4 per pound. Find "x" and "      Log On


   



Question 581682: "x" pounds of candy valued at $3.50 per pound is mixed with "y" pounds of candy valued at $4.30 per pound to produce 10 pounds of a mixture selling for $4 per pound. Find "x" and "y", the number of pounds of each type.
Answer by stanbon(75887) About Me  (Show Source):
You can put this solution on YOUR website!
"x" pounds of candy valued at $3.50 per pound is mixed with "y" pounds of candy valued at $4.30 per pound to produce 10 pounds of a mixture selling for $4 per pound. Find "x" and "y", the number of pounds of each type.
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Quantity Eq:::: x + y = 10 lbs
Value Eq::::::3.5x+4.3y = 4*10 dollars
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Multiply thru Quantity Eq by 35
Multiply Value Eq by 10
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35x + 35y = 350
35x + 43y = 400
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Subtract and solve for "y":
8y = 50
y = 6.25 lbs (amt. of $4.30 candy needed)
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Solve for "x":
x + y = 10
x + 6.25 = 10
x = 3.75 lbs (amt. of $3.50 candy needed)
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Cheers,
Stan H.
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