You can put this solution on YOUR website! What is tan^2Ө =1/3 using the interval 0 ≤ Ө < 2π
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tan(theta) = +-[1/sqrt(3)]
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Draw a right triangle:
tan = y/x so y = height = +-1 and x = base = +-sqrt(3)
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Find "r":
r = sqrt(1^2 + (sqrt(3))^2} = sqrt(4) = 2
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Since the height is +-1 and the hypotenuse is 2
the angle opposite "y" is pi/6 in the Q1; it is
(5/6)pi in Q2; it is (7/6)pi in Q3; and it is
(11/6)pi in Q4.
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Cheers,
Stan H.
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