SOLUTION: How do I solve the following using the relationship between natural logarithms, Ins, and the number e?
1)In(2m+3)=8
2)1.1+In x^2=6
3)e^x+1=30
Question 581589: How do I solve the following using the relationship between natural logarithms, Ins, and the number e?
1)In(2m+3)=8
2)1.1+In x^2=6
3)e^x+1=30 Answer by nerdybill(7384) (Show Source):
You can put this solution on YOUR website! 1)In(2m+3)=8
2m+3 = e^8
2m = e^8 - 3
m = (e^8 - 3)/2
m = 1488.98
.
2)1.1+In x^2=6
Ln x^2 = 6 - 1.1
x^2 = e^(6 - 1.1)
x = sqrt(e^(6 - 1.1))
x = 11.59
.
3)e^x+1=30
e^x=30-1
x = ln(30-1)
x = 3.37
