SOLUTION: y-6 (over )y=5 2 (over)3b-3 (over)4=1(6b) 4 (over) a+1=8 (over)2-a

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: y-6 (over )y=5 2 (over)3b-3 (over)4=1(6b) 4 (over) a+1=8 (over)2-a       Log On


   



Question 58151: y-6 (over )y=5 2 (over)3b-3 (over)4=1(6b)

4 (over) a+1=8 (over)2-a



Answer by ankor@dixie-net.com(22740) About Me  (Show Source):
You can put this solution on YOUR website!
y-6 (over )y=5 2 (over)3b-3 (over)4=1(6b)
4 (over) a+1=8 (over)2-a
:
%28y-6%29%2Fy+=+5+
Mult the eq by y, gets rid of the denominator and you have:
y - 6 = 5y
y - 5y = + 6
-4y = +6
y = 6/-4
y = -3/2
:
:
2%2F%283b%29+-+3%2F4+=+1%2F%286b%29
A good common denominator is 12b, mult eq by 12b and you have:
4(2) - 3b(3) = 2(1)
8 - 9b = 2
-9b = 2 - 8
-9b = -6
b = -6/-9
b = + 2/3
:
:
4%2F%28a%2B1%29+=+8%2F%282-a%29
Since there is only one term on each side of equal sign, you can cross mult here
4(2-a) = 8(a+1)
8 - 4a = 8a + 8
-4a - 8a = 8 - 8
-12a = 0
a = 0
:
Check in the original equation, can see that a has to = 0: 4/1 = 8/2
:
It's a good idea to check the solutions in the 1st two problems by subtitution
in the original equations.