SOLUTION: Can some please help me solve for x? ln (4x – 8) – ln (x-1) = ln 5

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: Can some please help me solve for x? ln (4x – 8) – ln (x-1) = ln 5      Log On


   

Question 581434: Can some please help me solve for x? ln (4x – 8) – ln (x-1) = ln 5
Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
+ln+%28+4x+-+8%29+%96+ln+%28+x-1+%29+=+ln+%28+5+%29+
+ln%284%29+%2B+ln%28+x-2+%29+-+ln%28+x-1+%29+=+ln%285%29+
++ln%28+x-2+%29+-+ln%28+x-1+%29+=+ln%285%29+-+ln%284%29+
+ln%28+%28+x-2+%29+%2F+%28+x-1+%29+%29+=+ln%28+5%2F4%29+
+%28+x-2+%29+%2F+%28+x-1+%29+=+5%2F4+
+4%2A%28+x-2%29+=+5%2A%28+x-1+%29+
+4x+-+8+=+5x+-+5+
+x+=+-3+
This can't be right because it gives me
+ln%28-20%29+ and +ln%28-4%29+
It is impossible to have ln( a negative number )
-------
I'll try something different
+%28+x-2+%29+%2F+%28+x-1+%29+=+1+-+%28+1%2F%28+x-1%29%29+
+1+-+%28+1%2F%28+x-1%29%29++=+5%2F4+
+1%2F%28+x-1+%29+=+4%2F4+-+5%2F4+
+1%2F+%28+x-1+%29+=+-+%281%2F4%29+
+x+=+-3+
Still impossible. I think either the problem can't be solved
or it was copied wrong.