SOLUTION: 1)The length of the rectangle is 1 more than width. The area is 12 square inches. Find the dimensions.

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: 1)The length of the rectangle is 1 more than width. The area is 12 square inches. Find the dimensions.      Log On


   

Question 581239: 1)The length of the rectangle is 1 more than width. The area is 12 square inches. Find the dimensions.
Answer by dfrazzetto(283) About Me  (Show Source):
You can put this solution on YOUR website!

L = W + 1
A = L x W = (W + 1)(W) = 12
W^2 + W - 12 = 0
(W+4)(W-3) = 0
W = -4 or 3, can't have negatives in rectangle widths, so w =3
L = 4