| 
 
 
| Question 580519:  How many different ways can a committee of 3 be selected from among the 55 staff members at a bank?
 Answer by jim_thompson5910(35256)
      (Show Source): 
You can put this solution on YOUR website! C(n,r) = (n!)/(r!(n-r)!) 
 C(55,3) = (55!)/(3!*(55-3)!)
 
 C(55,3) = (55!)/(3!*52!)
 
 C(55,3) = (55*54*53*52!)/(3!*52!)
 
 C(55,3) = (55*54*53)/(3!)
 
 C(55,3) = (55*54*53)/(3*2*1)
 
 C(55,3) = (157410)/(6)
 
 C(55,3) = 26235
 
 So there are 26235 different ways to form the committee (assuming order doesn't matter; ie, each member of the committee is of the same rank)
 | 
  
 | 
 |