Question 580247: Solve each system by substitution
Y=x-5
Y=4x-8
Need to learn how to help my daughter work these problems so I can be on the same page with her.
We need step by step directions if possible pretty please, it would've grealy appreciated...THANK YOU
Solve each system by elimination
4x-2y=-8
-4x+5y=14
Answer by jim_thompson5910(35256)   (Show Source):
You can put this solution on YOUR website! # 1
Hint: Since y = x - 5 and y = 4x-8, you can take the first equation y = x - 5 and replace 'y' with '4x-8' to get
y = x - 5
4x-8 = x - 5
From there, solve for x. Once you have the solution for x, use it to find y (by plugging the solution for x into either y = x - 5 or y = 4x-8)
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# 2
Hint:
If you add the two equations, you'll get
4x-2y=-8
+ -4x+5y=14
----------
3y = 6
From there, solve for y. Then use the solution of y to find x.
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