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Question 579953: numerator of a fraction is 1 less than the denominator. If the numerator and the denominator are both increased by 4, the new fraction will be 1/8 more than the original fraction. Find the original fraction.
I have done this: x+1/x original 4+(x+1)/4+x = (x+1)/x + 1/8
Answer by stanbon(75887)   (Show Source):
You can put this solution on YOUR website! numerator of a fraction is 1 less than the denominator. If the numerator and the denominator are both increased by 4, the new fraction will be 1/8 more than the original fraction. Find the original fraction.
I have done this:
(x-1)/x original
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Equation:
4+(x-1)/(4+x) = (x-1)/x + (1/8)
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Multiply thru by 8x(x+4) to get:
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[32x(x+4)] + [8x(x-1)] = [8(x+4)(x-1)] + [x(x+4)]
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32x^2+ 128x + 8x^2-8x = 8x^2+24x-32 + x^2+4x
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40x^2 + 120x = 9x^2 + 28x -32
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31x^2 + 92x +32
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I graphed it and found solutions at:
x = -2.5654 and x = -0.4024
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Cheers,
Stan H.
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