SOLUTION: 3/(x^2+4x+3) - 1/(x^2-9) =3/(x+1)(x+3)-1/(x-3)(x+3) =(3((x-3)-1(x+1))/(x+1)(x-3)(x+3) =3x-3-x-1/(x+1)(x^2-9) =2x-4/(x^3+x^2-9x-9) =2(x-2)/(x^3+x^2-9x-9)

Algebra ->  Polynomials-and-rational-expressions -> SOLUTION: 3/(x^2+4x+3) - 1/(x^2-9) =3/(x+1)(x+3)-1/(x-3)(x+3) =(3((x-3)-1(x+1))/(x+1)(x-3)(x+3) =3x-3-x-1/(x+1)(x^2-9) =2x-4/(x^3+x^2-9x-9) =2(x-2)/(x^3+x^2-9x-9)       Log On


   

Question 57990: 3/(x^2+4x+3) - 1/(x^2-9)
=3/(x+1)(x+3)-1/(x-3)(x+3)
=(3((x-3)-1(x+1))/(x+1)(x-3)(x+3)
=3x-3-x-1/(x+1)(x^2-9)
=2x-4/(x^3+x^2-9x-9)
=2(x-2)/(x^3+x^2-9x-9)
Answer by jaya_rohith1@yahoo.com(33) About Me  (Show Source):
You can put this solution on YOUR website!
2(x-2)/x^3+x^2-9x-9)