SOLUTION: The larger of two numbers is 14 less than four times the smaller number. The sum of the two numbers is 66. What are the two numbers?

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Question 579129: The larger of two numbers is 14 less than four times the smaller number. The sum of the two numbers is 66. What are the two numbers?
Found 2 solutions by dfrazzetto, mananth:
Answer by dfrazzetto(283) About Me  (Show Source):
You can put this solution on YOUR website!
x is larger number
y is smaller number
x = 4y-14
x+y = 66
4y-14 + y = 66
5y = 80
y= 16
x = 4(16) - 14 = 64 - 14 = 50
CHECK:
x + y = 50 + 16 = 66 √

Answer by mananth(16946) About Me  (Show Source):
You can put this solution on YOUR website!
smaller number be x
larger number = 4x-14

x+4x-14=66
5x-14=66
5x=80
/5
x= 16
First number = 16
second number = 4x-14
=4*16-14
=50
16 & 50 are the numbers