SOLUTION: 2(b+1)-(6+b)=-5 Justin had 35$ before spending q dollars on Jeans.how much money remains? The translation is ? Solve: 16(x+3)=4(4x+5)+28
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-> SOLUTION: 2(b+1)-(6+b)=-5 Justin had 35$ before spending q dollars on Jeans.how much money remains? The translation is ? Solve: 16(x+3)=4(4x+5)+28
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Question 578998: 2(b+1)-(6+b)=-5 Justin had 35$ before spending q dollars on Jeans.how much money remains? The translation is ? Solve: 16(x+3)=4(4x+5)+28 Answer by nyc_function(2741) (Show Source):
Justin had $35 before spending q dollars on Jeans. How much money remains? If he has $35 and spends q dollars, the remaining amount is (35 - q) dollars.
Solve for x:
16(x+3)= 4(4x+5)+28
16x + 48 = 16x + 20 + 28
16x + 48 = 16x + 48
16x - 16x = 48 - 48
0 = 0
Do you see we have the same quantity on both sides of the equation?
This means the answer will always be true for this equation.