SOLUTION: how would you solve 3^(x+4) = 6^(2x-5)? I don't know where to start... thank you so much!
Algebra
->
Exponential-and-logarithmic-functions
-> SOLUTION: how would you solve 3^(x+4) = 6^(2x-5)? I don't know where to start... thank you so much!
Log On
Algebra: Exponent and logarithm as functions of power
Section
Solvers
Solvers
Lessons
Lessons
Answers archive
Answers
Click here to see ALL problems on Exponential-and-logarithmic-functions
Question 578986
:
how would you solve 3^(x+4) = 6^(2x-5)?
I don't know where to start...
thank you so much!
Answer by
nerdybill(7384)
(
Show Source
):
You can
put this solution on YOUR website!
3^(x+4) = 6^(2x-5)
log 3^(x+4) = log 6^(2x-5)
(x+4)log 3 = (2x-5)log 6
(x+4)/(2x-5) = log 6/log 3
(x+4)/(2x-5) = 1.631
(x+4) = 1.631(2x-5)
x+4 = 3.2619x-8.155
4 = 2.2619x-8.155
12.155 = 2.2619x
5.376 = x