SOLUTION: find three consecutive odd integers such that 12 more than twice the sum of the first and third is equal to 15 less than five times the second.

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Question 578420: find three consecutive odd integers such that 12 more than twice the sum of the first and third is equal to 15 less than five times the second.
Answer by lwsshak3(11628) About Me  (Show Source):
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find three consecutive odd integers such that 12 more than twice the sum of the first and third is equal to 15 less than five times the second.
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let x = 1st consecutive odd integer
x+2 = 2nd consecutive odd integer
x+4 = 3rd consecutive odd integer
..
2(x+x+4)+12=5(x+2)-15
4x+8+12=5x+10-15
4x+20=5x-5
x=25
x+2=27
x+4=29
ans:
The three consecutive odd integers are: 25, 27, and 29