SOLUTION: I need to find the X and Y intercepts of the two equations. 4x-2y=6 and x-y/2=-1.5. I have already found the X and Y intercepts of each but now I need to find the "solution" to

Algebra ->  Linear-equations -> SOLUTION: I need to find the X and Y intercepts of the two equations. 4x-2y=6 and x-y/2=-1.5. I have already found the X and Y intercepts of each but now I need to find the "solution" to       Log On


   



Question 578060: I need to find the X and Y intercepts of the two equations. 4x-2y=6 and x-y/2=-1.5. I have already found the X and Y intercepts of each but now I need to find the "solution" to the problem. I'm very confused on how to find the solution. Here is what I have so far:
For equation 4x-2y=6
The X intercept is 3/2
The Y intercept is -3
For equation x-y/2=-1.5
The X intercept is -1.5
The Y intercept is 3
I'm also needing to graph these. I can graph them with no problems, it's just finding the "solution" that is throwing me off. I'm not quite sure what they mean by it.

Answer by josmiceli(19441) About Me  (Show Source):
You can put this solution on YOUR website!
The "solution" is the point ( x1,y1 ) that satisfies
both equations. It is the intersection of the
2 straight lines. As long as they are straight lines, they
can only intersect at 1 point.
------------------------
(1) +4x+-+2y+=+6+
(2) +x+-+%281%2F2%29%2Ay+=+-%283%2F2%29+
---------------------
Multiply both sides of (2) by 2
(2) +2x+-+y+=+-3+
Divide both sides of (1) by 2
(1) +2x+-+y+=+3+
------------------
Because these lines only differ by a constant,
they are parallel lines, and can have no
intersection, and therefore no solution
Here's a plot of the lines:
+graph%28+400%2C+400%2C+-10%2C+10%2C+-10%2C+10%2C+2x+%2B+3%2C+2x+-+3+%29+