SOLUTION: factor completely. 9x^7-45x^6+18x^5

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Question 578009: factor completely.
9x^7-45x^6+18x^5

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

9x%5E7-45x%5E6%2B18x%5E5 Start with the given expression.


9x%5E5%28x%5E2-5x%2B2%29 Factor out the GCF 9x%5E5.


Now let's try to factor the inner expression x%5E2-5x%2B2


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Looking at the expression x%5E2-5x%2B2, we can see that the first coefficient is 1, the second coefficient is -5, and the last term is 2.


Now multiply the first coefficient 1 by the last term 2 to get %281%29%282%29=2.


Now the question is: what two whole numbers multiply to 2 (the previous product) and add to the second coefficient -5?


To find these two numbers, we need to list all of the factors of 2 (the previous product).


Factors of 2:
1,2
-1,-2


Note: list the negative of each factor. This will allow us to find all possible combinations.


These factors pair up and multiply to 2.
1*2 = 2
(-1)*(-2) = 2

Now let's add up each pair of factors to see if one pair adds to the middle coefficient -5:


First NumberSecond NumberSum
121+2=3
-1-2-1+(-2)=-3



From the table, we can see that there are no pairs of numbers which add to -5. So x%5E2-5x%2B2 cannot be factored.


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Answer:


So 9x%5E7-45x%5E6%2B18x%5E5 simply factors to 9x%5E5%28x%5E2-5x%2B2%29


In other words, 9x%5E7-45x%5E6%2B18x%5E5=9x%5E5%28x%5E2-5x%2B2%29.